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3 February, 05:53

In a similar analysis, a student determined that the percent of water in the hydrate was 25.3%. the instructor informed the student that the formula of the anhydrous compound was cuso4. calculate the formula for the hydrated compound.

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  1. 3 February, 08:45
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    Answer is: f ormula for the hydrated compound is CuSO ₄·3H₂O.

    ω (H₂O) = 25,3% = 0,253.

    ω (CuSO₄) = 100% - 25,3%.

    ω (CuSO₄) = 74,7% = 0,747.

    ω (H₂O) : M (H₂O) = ω (CuSO₄) : M (CuSO₄).

    0,253 : M (H₂O) = 0,747 : 159,6 g/mol.

    M (H₂O) = (0,253 · 159,6 g/mol) : 0,747.

    M (H₂O) = 54 g/mol.

    N (H₂O) = 54 g/mol : 18 g/mol.

    N (H₂O) = 3.
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