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26 December, 11:27

What volume of 0.200 m h3po4 will completely react with 50.00 ml of 0.200 m naoh?

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  1. 26 December, 15:02
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    The complete balanced reaction for this would be:H3PO4 + 3NaOH - - - > Na3PO4 + 3H2OSo we can see that 3 moles of NaOH reacts with 1 mole of H3PO4.

    moles NaOH = 0.2 M * 0.05 L = 0.01 molesmoles H3PO4 = 0.01 moles NaOH * (1 mole H3PO4 / 3 moles NaOH) = 0.00333 moles

    So the volume required would be:V = 0.00333 moles / (0.200 moles / L) V = 0.0167 L = 16.7 mL
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