How many grams of chromium are required to react with 125ml of 0.75m cuso4?

Chromium and copper (ii) sulfate react according the reaction below;

2Cr + 3CuSO4 = 3Cu + Cr2 (SO4) 3

We can calculate the number of moles of CuSO4 present;

no of moles of CuSO4 = 0.75 * 0.125 = 0.09735 moles

According to the reaction the mole ratio is 2 : 3

Moles of Chromium = (0.09735 * 2) / 3

= 0.0625 Moles

Mass of chromium = 0.0625 moles * 52 g/mole

= 3.25 g of chromium