Calculate the [oh-] value of each aqueous solution. oven cleaner, with [h3o+]=1.0*10-12m

The oven cleaner has [H⁺ (aq) ] as 1.0 x 10⁻¹² M. hence the pH of the solution can be calculated by using the equation, pH = - log₁₀[H⁺ (aq) ]

hence, pH = - log₁₀ (1.0 x 10⁻¹² M)

= 12

Since pH + pOH = 14

12 + pOH = 14

pOH = 2

pOH = - log₁₀[OH⁻ (aq) ]

2 = - log₁₀[OH⁻ (aq) ]

[OH⁻ (aq) ] = 1.0 x 10⁻² M

Hence the [OH⁻] in oven cleaner is 1.0 x 10⁻² M