The ksp of iron (ii) hydroxide, fe (oh) 2, is 4.87 * 10-17. calculate the molar solubility of this compound.

When iron hydroxide dissolves, it dissociates as follows

Fe (OH) ₂ - - > Fe²⁺ + 2OH⁻

molar solubility is the number of moles of solute that can be dissolved is a 1 L solution

if molar solubility of Fe (OH) ₂ is x then molar solubility of Fe²⁺ is x and OH⁻ is 2x

the solubility product constant - ksp formula is;

ksp = [Fe²⁺][OH⁻]²

ksp = (x) (2x) ²

ksp = x * 4x²

ksp = 4x³

ksp = 4.87 x 10⁻¹⁷

4x³ = 4.87 x 10⁻¹⁷

x = 2.30 x 10⁻⁶ M

molar solubility of Fe (OH) ₂ is 2.30 x 10⁻⁶ M