A substance contains 35.0 g nitrogen, 5.05 g hydrogen, and 60.0 g of oxygen. how many grams of hydrogen are there in a 153-g sample of this substance

M (N) = 35.0 g

m (H) = 5.05 g

m (O) = 60.0 g

m₁=153 g

m₀=m (N) + m (H) + m (O)

w (H) = m (H) / m₀=m (H) / [m (N) + m (H) + m (O) ]

m₁ (H) = w (H) m₁=m₁m (H) / [m (N) + m (H) + m (O) ]

m₁ (H) = 153*5.05/[35.0+5.05+60.0]=7.72 g

7.72 g