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12 November, 19:53

Calculate the molarity of a solution prepared by dissolving 12.5 g of Na2CrO4 in enough water to produce a solution with a volume of 810. mL.

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  1. 12 November, 22:22
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    0.0953M

    Explanation:

    First, let us calculate the number of mole present in 12.5g of Na2CrO4.

    Molar Mass of Na2CrO4 = (23x2) + 52 + (16x4) = 46 + 52 + 64 = 162g/mol

    Mass of Na2CrO4 = 12.5g

    Number of mole = ?

    Number of mole = Mass / Molar Mass

    mole of Na2CrO4 = 12.5/162 = 0.0772mol

    Now, we can calculate for the molarity as follows:

    Mole = 0.0772mol

    Volume = 810mL = 810/1000 = 0.81L

    Molarity = ?

    Molarity = mole / Volume

    Molarity = 0.0772mol/0.81L

    Molarity = 0.0953M
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