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4 September, 03:34

A 6.34L sample of hydrogen gas exerts a pressure of 1.52 atm at 298K. What temperature would be required for it to have a volume of 4.98L and a pressure of 0.720 atm?

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  1. 4 September, 07:17
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    There is a temperature of 111 K required.

    Explanation:

    Step 1: Data given

    Volume of hydrogen gas = 6.34 L

    Pressure = 1.52 atm at 298 K

    The volume of the gas at a pressure of 0.720 atm is 4.98 L

    Step 2:

    (P1*V1) / T1 = (P2*V2) / T2

    ⇒ with P1 = the pressure of the hydrogen gas = 1.52 atm

    ⇒ with V1 = the volume of the hydrogen gas = 6.34 L

    ⇒ with T1 = the temperature of the hydrogen gas = 298 K

    ⇒ with P2 = the changed pressure of the gas = 0.720 atm

    ⇒ with V2 = the changed volume of the gas = 4.98 L

    ⇒ with T2 = the temperature of the gas at 0.720 atm and 4.98L

    (1.52*6.34) / 298 = (0.720*4.98) / T2

    0.0323 = 3.5856/T2

    T2 = 110.88 K ≈111K

    There is a temperature of 111 K required.
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