Calculate the molarity of a solution prepared by dissolving 195 g of sodium chloride (NaCl) in enough water to make 2.8 liters of solution.

molarity of a solution = 1.192 M

Explanation:

molarity [=] mol compound / L solution

∴ mass NaCl = 195 g

∴ molar mass NaCl = 58.44 g/mol

⇒ moles NaCl = (195 g) * (mol/58.44 g) = 3.34 mol

∴ Volumen solution = 2.8 L

⇒ Molarity NaCl solution = (3.34 mol) / (2.8 L) = 1.192 M