What are the [H+] and [OH-] for a substance with a ph of 9.2?

The answer to your question is [H⁺] = 6.31 x 10⁻¹⁰ M [OH⁻] = 1.58 x 10⁻⁵ M

Explanation:

Data

[H⁺] = ?

[OH⁻] = ?

pH = 9.2

Process

To find the answer to this question we must start by using the formula of pH and simplify to find the [H⁺] then calculate the pOH to find the [OH⁻]

1. - Write the formula of pH

pH = - log [H⁺]

2. - Find the [H⁺]

9.2 = - log[H⁺]

-Solve for [H⁺]

[H⁺] = antilog (-9.2)

-Result

[H⁺] = 6.31 x 10⁻¹⁰ M

3. - Calculate the pOH

pH + pOH = 14

-Solve for pOH

pOH = 14 - 9.2

-Result

pOH = 4.8

4. - Calculate the [OH⁻]

-Substitution

4.8 = - log [OH⁻]

-Solve for [OH⁻]

[OH⁻] = antilog (-4.8)

-result

[OH⁻] = 1.58 x 10⁻⁵ M