Ask Question
27 March, 05:53

What is the molality of a solution containing 2.6 moles of sugar and 6 kg water?

+5
Answers (2)
  1. 27 March, 07:33
    0
    Answer: 0.4333moles/kg.

    Explanation: Molality is a property of a solution and is defined as the number of moles of solute per kilogram of solvent. In the given problem the sugar is the solute and the water is the solvent, so to calculate the molality we need to divide the moles of sugar by the kilograms of water:

    molality=m=moles of solute/kilograms of solvent

    m=2.6moles of sugar/6kg of water

    m=0.4333moles/kg.
  2. 27 March, 08:15
    0
    Convert kg into L, then take the moles and divide it by the L of water
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “What is the molality of a solution containing 2.6 moles of sugar and 6 kg water? ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers