Ammonium hydroxide is neutralized by sulfuric acid to produce ammonium sulfate and water. It will make ___ mol ammonium sulfate when you neutralize 11.00 g ammonium hydroxide. __ NH4OH + __ H2SO4 → __ (NH4) 2SO4 + __ H2O

1) Ammonium hydroxide is neutralized by sulfuric acid to produce ammonium sulfate and water. It will make 0.157 mol ammonium sulfate when you neutralize 11.00 g ammonium hydroxide.

2) 2NH₄OH + H₂SO₄ → (NH₄) ₂SO₄ + 2H₂O.

Explanation:

Firstly, we should balance the equation of heptane combustion. We can balance the equation by applying the conservation of mass to the equation. The balanced equation is: 2NH₄OH + H₂SO₄ → (NH₄) ₂SO₄ + 2H₂O. This means that every 2.0 moles of ammonium hydroxide (NH₄OH) will produce 1.0 mole of ammonium sulfate (NH₄) ₂SO₄ when it is neutralized by sulfuric acid. We need to calculate the no. of moles in 11.0 g of ammonium hydroxide that is neutralized using the relation: n = mass/molar mass.

n of 11.0 g of ammonium hydroxide (NH₄OH) = mass/molar mass = (11.0 g) / (35.04 g/mol) = 0.314 mol.

Using cross multiplication:

2.0 moles of NH₄OH make → 1.0 mole of (NH₄) ₂SO₄.

0.314 mol of NH₄OH make →? moles of (NH₄) ₂SO₄.

∴ The no. of moles of (NH₄) ₂SO₄ that will be made from neutralizing (11.0 g) of NH₄OH = (0.314 mol) (1.0 mol) / (2.0 mol) = 0.157 mol.

∴ Ammonium hydroxide is neutralized by sulfuric acid to produce ammonium sulfate and water. It will make 0.157 mol ammonium sulfate when you neutralize 11.00 g ammonium hydroxide.