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14 March, 17:43

A 3.664 g sample of a monoprotic acid was dissolved in water. It took 20.27 mL of a 0.1578 M NaOH solution to neutralize the acid. Calculate the molar mass of the acid. (Monoprotic refers to an acid that provides only one H+).

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  1. 14 March, 19:51
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    Molar mass of monoprotic acid is 1145g/mol.

    Explanation:

    The reaction of a monoprotic acid (HX) with NaOH is:

    HX + NaOH → H₂O + NaX

    That means 1 mole of acid reacts with 1 mole of NaOH

    If the neutralization of the acid spent 20.27mL of a 0.1578 M NaOH solution. Moles of NaOH are:

    0.02027L * (0.1578mol / L) = 3.199x10⁻³ moles NaOH ≡ moles HX.

    As mass of the sample is 3.664g, molar mass of the acid is:

    3.664g / 3.199x10⁻³ moles = 1145g/mol
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