A 4,000 mL solution of AgNO3 contains 17.00 g of solute in water. Calculate the molar concentration of the solution.

The molarity is moles/liters.

First, convert 4,000 mL to L:

4000 mL - - > 4 L

Now, you must convert the 17 g of solute to moles by dividing the number of grams by the molar mass. The molar mass of AgNO3 is 169.87 g/mol:

17 / 169.87 =.1

Now that you have both the number of moles and the liters, plug them into the initial equation of moles/liters:

.1/4 =.025

The answer is 0.03 M