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14 August, 00:13

What mass of lithium phosphate is needed to prepare 500. ml of a solution having a lithium ion concentration of 0.125 m?

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  1. 14 August, 03:57
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    First, we must calculate the moles of lithium ions required using:

    Concentration = moles / liter

    500 ml = 0.5 L

    0.125 = moles / 0.5

    moles = 0.0625

    Lithium phosphate has the formula Li₃PO₄, meaning each mole of lithium phosphate releases three moles of lithium ions. The moles of lithium phosphate required will be:

    0.0625 / 3 = 0.021 mol

    The mass of one mole of lithium phosphate is 116 g/mol

    Mass of lithium phosphate required = 0.021 x 116

    Mass of lithium phosphate required = 2.42 grams
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