Assume the average weight of an American adult male is 180 pounds with a standard deviation of 34 pounds. The distribution of weights follows a normal distribution. What is the probability that a man weighs somewhere between 120 and 155 pounds?

Question

Mathematics

Gauge Cantrell

14 July, 11:20

Assume the average weight of an American adult male is 180 pounds with a standard deviation of 34 pounds. The distribution of weights follows a normal distribution. What is the probability that a man weighs somewhere between 120 and 155 pounds?

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Answers (1)

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Dania · Answer 1

Step-by-step explanation:

Find a-score of both

z-score = (x-mean) / SD

for 120

z = (120 - 180) / 34 = - 1.765

For 155

z = (155-180) / 34 = - 0.735

The probability to look for using z-score table is;

P (-1.765