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10 June, 09:47

Kevin has $4.85 in nickels and dimes. If he has 34 fewer dimes than nickels, how many coins (nickels and dimes) does he have altogether?

A. 74 coins

B. 75 coins

C. 76 coins

D. 77 coins

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Answers (2)
  1. 10 June, 13:07
    0
    the correct answer is C

    Step-by-step explanation:

    Set the 34 more nickels aside.

    --> pairs of 1 nickel & 1 dime each worth 15 cents & a total of $3.15 ($4.85 - $1.70)

    315/15 = 21 pairs

    --> 21 dimes and 55 nickels
  2. 10 June, 13:20
    0
    if x = the number of nickles and x-34 = the number of dimes then. 05x +.10 (x-34) = 4.85 or. 15x = 8.25 x = 55

    So, nickles = x = 55

    dimes = (x-34) = 21

    55 + 21 = 76 So, that means your answer is C. 76 coins
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