Ask Question
3 December, 16:40

Cristobal is comparing the membership club fees at two different bookstores. At the first bookstore, it costs $17.05 annually to be a member of the club, but he will save 15% on all his purchases. At the second bookstore, it costs $28.57 annually to be a member of the club, but he will save 25% on all his purchases. How much does Cristobal need to spend in a year for the membership at the second bookstore to be the better value? A. $115.21 B. $144.00 C. $86.64 D. $132.48

+4
Answers (1)
  1. 3 December, 19:42
    0
    A) Cristobal need to spend $115.2 in a year for the membership at the second bookstore to be the better value.

    Step-by-step explanation:

    Let x : Amount Cristobal needs to spend for 2nd membership to be better.

    At First bookstore:

    Member ship fee = $17.05

    The savings on purchase = 15%

    So, actual payment = x - (15% of x)

    = x - 0.15 x = 0.85 x

    So, the total payment in first bookstore

    = Membership fee + Purchase payment

    = $17.05 + 0.85 x

    or, the amount paid at first book store = $17.05 + 0.85 x

    At Second bookstore:

    Member ship fee = $28.57

    The savings on purchase = 25%

    So, actual payment = x - (25% of x) = x - 0.125 x = 0.75 x

    So, the total payment in first bookstore = $28.57 + 0.75 x

    Now, payment made at second store >Payment at first store

    ⇒$28.57 + 0.75 x > $17.05 + 0.85 x

    or, 18-57 - 17-05 > 0.85 x - 0.75 x

    or, 0.10x < 11.52

    or, x < 11.52/0.10 = 115.2

    or, x < 115.2

    Hence, Cristobal need to spend $115.2 in a year for the membership at the second bookstore to be the better value.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Cristobal is comparing the membership club fees at two different bookstores. At the first bookstore, it costs $17.05 annually to be a ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers