The polynomial f (x) is written in factored form:

f (x) = (x - 6) (x + 5) (x - 9)

What are the zeros of the polynomial function?

x = 6, x = - 5, x = 9

x = 6, x = 5, x = 9

x = - 6, x = 5, x = - 9

x = - 6, x = 6, x = - 5, x = 5, x = - 9, x = 9

x = 6, x = - 5, x = 9

if f (x) = (x-6) (x+5) (x-9)

Step-by-step explanation:

The zeros of a polynomial in factored form can be found by setting the polynomial equal to zero and then realizing if a product is zero, then at least one of it's factors is zero.

So we have the zero's are the x's that satisfy

(x-6) (x+5) (x-9) = 0.

We just need to solve three equations:

x-6=0

This can be solved by adding 6 on both sides: x=6

x+5=0

This can be solved by subtracting 5 on both sides: x=-5

x-9=0

This can be solved by adding 9 on both sides: x=9

The solutions are in { 6,-5,9 }.

x = 6, x = - 5, x = 9

Step-by-step explanation:

If the polynomial f (x) is written in factored form, f (x) = (x - 6) (x + 5) (x - 9), the zeros of the polynomial function are x = 6, x = - 5, x = 9.

x-6=0 x = 6

x+5=0 x = - 5

x-9=0 x = 9

Therefore, x = 6, x = - 5, x = 9 would be the correct answer.