Algebra

Solve these simultaneous questions via elimination method:

2x + 3y = 12

4x - 3y = 6

(2x + 3y = 12) x (-2)

(4x - 3y = 6) x 1

-4x - 6y = - 24

4x - 3y = 6

You can cancel out the x values by adding the two equations together.

(-4x + 4x) + (-6y - 3y) = (-24 + 6)

-9y = - 18

y = 2

Solve for x now ...

4x - 3 (2) = 6

4x - 6 = 6

4x = 12

x = 3

Check ... (x = 3, y = 2)

2 (3) + 3 (2) = 12

6 + 6 = 12

12 = 12 < - this works!

4 (3) - 3 (2) = 6

12 - 6 = 6

6 = 6 < - this works!

2x + 3y = 12

2*3 6 x = 3 because 2 times 3 equals 6y = 2 because 3 times 2 equals 6. 6+6=12.

4 (3) - 3 (2) = 6 / / / / 12 6 = 6

(I'm copy-pasting from the work I just did on another tab. I know the page would reload)