Physics problem: piston? The piston of a hydraulic automobile lift is 0.300 m in diameter. 1. What gauge pressure, in pascals, is required to lift a car with a mass of 1200 kg?

Given:

d = 0.3 m, piston diameter

m = 1200 kg, mass to be lifted

The piston area is

A = (n/4) * (0.3 m) ² = 0.0707 m².

Let p (Pa) be the required piston pressure.

Then (p N/m²) * (0.0707 m²) = (1200 kg) * (9.8 m/s²)

p = 1.6637 x 10⁵ Pa = 166.4 kPa

Answer: 1.664 x 10⁵ Pa or 166.4 kPa

Pressure is given by:

P=F/A

force=1200*10=12000 N

Area=pi*r^2=3.14*0.15^2

=0.07065 m^2

Thus;

P=12000/0.7065

P=169,851.38 N/m^2

but

1 N/m^2=1 Pa

thus our pressure is:

169,851.38 Pa