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12 February, 01:17

A sled of mass 28 kg slides across the ground with a friction force of 200.3 N. What is k between the sled and the ground?

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  1. 12 February, 04:49
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    K=Frictional Force/Normal Force

    Normal force would be mg, since it's not on an incline.

    Normal Force = 28 kg*9.8 m/s^2 = 274.4 N

    200.3 N/274.4 N = 0.73
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