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15 January, 16:35

A 96lb boy is standing in an elevator. Find the force on the boy's feet when the elevator (a) stands still (b) moves downward at a constant velocity of 3 ft/d (c) accelerates downward with an acceleration of 4.0 ft/s2, and (d) accelerates upward with an acceleration of 4.0ft/s2

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  1. 15 January, 19:18
    0
    a) When the elevator is at rest

    R = mg

    R = force on the boy's feet = 96 x 32

    = 3072 unit.

    b) When the elevator moves with uniform velocity, net force on the boy = 0

    R = mg

    force on the boy's feet = 96 x 32

    = 3072 unit

    c) When the elevator moves with acceleration a downwards

    Reaction force R = mg - ma

    = m (g-a)

    = 96 (9.8 - 4)

    = 556.8 unit

    d)

    When the elevator moves with acceleration a upwards

    Reaction force R = mg + ma

    = m (g+a)

    = 96 (9.8 + 4)

    = 1324.8 poundal
  2. 15 January, 19:38
    0
    mass of boy, m = 96 lb

    acceleration due to gravity, g = 32 ft/s²

    (a) When the elevator is stands still

    Force, F = m g

    F = 96 x 32 = 3072 pounds

    (b) When the elevator moves with constant velocity

    F = mg = 3072 pounds

    (c) When the elevator moves downwards with constant acceleration

    F = mg - ma

    F = 96 (32 - 4)

    F = 2688 pounds

    (d)

    When the elevator moves upwards with constant acceleration

    F = mg + ma

    F = 96 (32 + 4)

    F = 3456 pounds
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