A 0.25 kg arrow with a velocity of 12 m/s to the west strikes and pierces the center of a 6.8 kg target. What is the final velocity of the combined mass

Answer:20/47 meter per second

Explanation:

Mass of arrow (ma) = 0.25kg

Velocity of arrow (va) = 12m/s

Mass of target (mt) = 6.8kg

Velocity of target (vt) = 0 since target is at rest

Conservation of linear momentum says that:

maxva+mtxvt = (ma+mt) V

V = (maxva+mtxvt) / (ma+mt)

V = (0.25x12+6.8x0) / (0.25+6.8)

V=3 / (7.05)

V=20/47 meter per second