a car with an initial velocity of 10ms north was accelerated for 6 second until it ha a final velocity of 25ms north, what is the cars acceleration?

Answer:a=2.5m/s^2

Explanation:

A=v-u/t

A = 25-10/6

A = 15/6

A=2.5m/s^2

2 1/2 m/s^2 or 2.5m/s^2

Explanation:

From the question

final velocity v = 25m/s

Initial velocity u = 10m/s

time = 6 seconds

acceleration a = ?

Using the equation for linear motion

v = u + at

25 = 10 + a x 6

25 = 10 + a6

Subtract 10 from both sides

25-10 = 10 + a6 - 10

25 - 10 = 10 - 10 + a6

15 = a6

Divide both sides by 6

15/6 = a6/6

5/2 = a

a = 2 1/2 m/s^2 or 2.5m/s^2