Calculate the rotational inertia of a meter stick, with mass 0.390 kg, about an axis perpendicular to the stick and located at the 21.1 cm mark. (Treat the stick as a thin rod.)

0.0651 kgm²

Explanation:

Parameters given:

Mass of meter stick, m = 0.39 kg

Distance of axis from center of meter stick, D = 50 - 21.1 cm = 28.9 cm = 0.289 m

The moment of inertia of a thin rod about an axis that is perpendicular to it and is located at a particular distance, D, from its center is given as:

I = 1/12 * m * L² + m * D²

I = (1/12 * 0.39 * 1²) + (0.39 * 0.289²)

I = 0.325 + 0.326

I = 0.0651 kgm²