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24 May, 23:29

A baseball is popped straight up into the air and has a hang-time of 6.25 S.

Determine the height to which the ball rises before it reaches its peak. (Hint: the

time to rise to the peak is one-half the total hang-time.)

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  1. 25 May, 01:12
    0
    47.9 m

    Explanation:

    Given:

    y₀ = 0 m

    t = 6.25/2 = 3.125 s

    v = 0 m/s

    a = - 9.8 m/s²

    Find: y

    y = y₀ + vt - ½ at²

    y = 0 + (0) (3.125) - ½ (-9.8) (3.125) ²

    y = 47.9 m
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