Ask Question
24 August, 09:52

a stone is thrown straight upwards from the edge of a 24.0 m high cliff. It just misses the cliff on the way down, and it hits the ground below with a velocity of - 42.3 m/s. With what velocity was the stone thrown upward initially?

+3
Answers (1)
  1. 24 August, 12:05
    0
    47.5 m/s

    Explanation:

    Given:

    Δy = - 24.0 m

    v = - 42.3 m/s

    a = - 9.8 m/s²

    Find: v₀

    v² = v₀² + 2aΔy

    v² = (-42.3 m/s) ² + 2 (-9.8 m/s²) (-24.0 m)

    v = 47.5 m/s
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “a stone is thrown straight upwards from the edge of a 24.0 m high cliff. It just misses the cliff on the way down, and it hits the ground ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers