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20 June, 12:23

2 cycleists, 90 miles apart starting riding toward each other at some times one cycles twice as fast as the other if they meet 2 hrs later at what average speed is each cyclist traveling

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  1. 20 June, 13:10
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    Average speed of the first car = 15 miles/hr

    Average speed of the second car = 30 miles/hr

    Explanations:

    distance = d = 90 miles

    Time = 2 hrs

    let speed of first cyclist = v

    speed of second cyclist = 2v

    relative speed = v + 2v = 3v

    using relative speed = Total distance/Total time

    3v = 90/2

    3 v=45

    v=15 miles/hr

    so speed of first cyclist = 15 miles/hr

    speed of second cyclist = 2 (15) = 30 miles/hr
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