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20 January, 18:10

A student conducted an experiment to measure the acceleration due to gravity 'g' of a simple pendulum.

Length of thread, l/m : 0.35

Time for 20 oscillations, t/s : 24.1

Length of thread, l/m : 0.65

Time for 20 oscillations : 3.24

Length of thread, l/m : 1.00

Time for 20 oscillations : 4.01

Lenght of thread, l/m : 1.45

Time for 20 oscillations : 47.5

Length of thread : 1.95

Time for 20 oscillations : 56.3

Given that the realtion between the period 'T', the length of the pendulum 'l' and the acceleration due to gravity 'g' is T=2 (pi) √ (l/g), find the value of 'g'.

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Answers (1)
  1. 20 January, 19:40
    0
    I think i used calulater and it gives me 47.5
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