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27 March, 08:45

An object is thrown upward with a speed of 14 m/s on the surface of planet X where the acceleration due to gravity is 3.5 m/s2. How long, in seconds, does it take for the object to reach the maximum height?

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  1. 27 March, 11:53
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    U = 14 m/s, g = 3.5 m/s². At maximum height, v = 0

    v = u - gt

    0 = 14 - 3.5t

    3.5t = 14

    t = 14/3.5

    t = 4

    time = 4 seconds
  2. 27 March, 11:59
    0
    The maximum height of the object is where the final velocity becomes zero. The final velocity is obtained by,

    Vf = V1 - gt

    Substituting the known values,

    0 = 14 m/s - (3.5 m/s²) t

    The value of t is 4 seconds.
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