A gas has a pressure of 0.410 atm and volume of 32 L. At what pressure, would the volume of the gas change to 28 L

The question here follows the ideal gas law, so we can say that the ideal gas equation is applicable which is PV = nRT

where:P is pressure, V is volume, n is number of moles, R is universal gas constant, andT is temperature.

When the right-hand side of the equation is constant, P₁V₁ = P₂V₂ this is the existing relationship,

Substituting the given will give us: (0.410 atm) (32 L) = (P₂) (28 L) P₂ = 0.4686